Contoh Soal Eksponen Kelas 10 Dan Pembahasannya Kurikulum 2013

Yo what’s up people, today we’re gonna talk about something that might make your brain wanna explode, but fear not, your boy’s got your back. We’re talking about eksponen dan logaritma, woo!

Fungsi Logaritma Eksponensial Eksponen

exponent image

Apa itu fungsi logaritma eksponensial eksponen? well, it basically means a logarithmic function that is written as an exponential function. confusing much? basically it’s just a function that involves both logarithms and exponents, and they’re kinda like a power duo in the math world.

Mengapa harus belajar tentang ini? well, aside from just being cool (because anything with exponents is cool, duh), it’s actually really useful in various fields like science, finance, and engineering. Plus, it’s gonna be super helpful in acing those math exams.

Cara menggunakan fungsi logaritma eksponensial eksponen? well, first we gotta understand the formula for it which is y = bx where b is the base of the exponential function and x is the logarithmic function. From there, it’s just a matter of plugging in values and solving for the unknown variable.

Contoh soal? too easy. Let’s say we have the equation y = 2x+1 and we need to find the value of x when y equals 8. Using basic algebra, we can simplify the equation to 2x+1 = 8 and then solve for x. The answer is x equals 2, because 22+1 equals 8. See, easy peasy.

Contoh Soal Eksponen Kelas 10 Dan Pembahasannya

contoh soal

Lanjut kita ke contoh soal eksponen kelas 10. Soalnya adalah: Tentukanlah nilai dari 100log107 + 7log492 + 10log52.

Apa ini bahasa alien? not really. It’s actually just a matter of using the properties of logarithms and exponents to simplify the equation. First, we can rewrite 100log107 as 72log107 since 100 can be expressed as 72. Then, we have 72log107 which can be further simplified as 7log1072 using the properties of exponents. From there, we can simplify it to 7log1049 which equals 49. Moving onto the next part of the equation, we can rewrite 7log492 as 2 using the properties of logarithms. Lastly, we can rewrite 10log52 as 2log510 and since log510 can be simplified as log52 + log55, we have 2log52 x 5 which equals 10. And that’s the answer, 49 + 2 + 10 equals 61.

Well folks, that concludes our little chat about eksponen and logaritma. Who knew math could actually be kinda fun, am I right? Til next time, stay curious!

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